A metallic element has a density of , a lattice constant of
and an atomic weight
. Calculate the number of atoms per unit cell of this element and predict its lattice crystal structure.
We are asked to calculate the number of atoms per unit cell of a metallic element and predict its lattice structure. Let’s solve it step by step. Given data: * Density, ( \rho = 2.70 \text{ g/cm}^3 ) * Lattice constant, ( a = 4.0495 , \text{Å} = 4.0495 \times 10^{-8} , \text{cm} ) * Atomic weight, ( M = 26.9815 \text{ g/mol} ) * Avogadro's number, ( N_A = 6.022 \times 10^{23} , ____ __________ _______ _____ _________.
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with a number density of atoms
calculate:
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(i) and (ii)
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at
and
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.
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is
.
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