Question

A manurial trial with six levels of Farmyard Manure (FYM) was carried out in a randomised block design with 4 replications at the experimental station Junagarh with a new study the rate of decomposition of organic matters in soil and its synthetic capacity in soil on cotton crop. The yield per plot in kg for different levels of FYM and replications is given below:

Cotton Yield Per Plot (in Kg)

Levels of FYM

Replications
I II III IV
1 6.90 4.60 4.40 4.81
2 6.48 5.57 4.28 4.45
3 6.52 7.60 5.30 4.45
4 6.90 6.65 6.75 7.75
5 6.00 6.18 6.50 5.50
6 7.90 7.57 6.80 6.62

Carry out the Analysis of Variance test and draw the conclusions. 

29 Apr 2025
Answer :
Word Count : 790
To carry out ANOVA (Analysis of Variance) for a Randomized Block Design (RBD), we need to analyze the total variation in the data and partition it into: * Variation due to treatments (FYM levels), * Variation due to blocks (replications), * Error (residual) variation. --- ### Step 1: Notation and Data Let’s denote: * t = 6 (number of treatments, i.e., FYM levels) * r = 4 (number of replications) * Total number of observations (n) = 24 Let’s denote the observations as $Y_{ij}$, where: * $i = 1 \text{ to } t = 6$ (treatments), * $j = 1 \text{ to } r = 4$ (replications) --- ### Step 2: Data Summary Let’s compute row totals (T\_i) and column totals (R\_j). | FYM Level | R1 | R2 | R3 | R4 | Row Total (Tᵢ) | Row Mean | | ------------------ | ----- | ----- | ----- | ----- | ------------------------ | ------------ | | 1 | 6.90 | 4.60 | 4.40 | 4.81 | 20.71 | 5.1775 | | 2 | 6.48 | 5.57 | 4.28 | 4.45 | 20.78 | 5.195 | | 3 | 6.52 | 7.60 | 5.30 | 4.45 | _______ ___ ________ ___ ____ _______ _____ _________ ___ _____ _________ ______.
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