Question
A library wants to improve its service facilities in terms of the waiting time of its borrowers. The library has two counters at present and borrowers arrive according to Poisson distribution with arrival rate 2 every 10 minutes and service time follows exponential distribution with a mean of 15 minutes. The library has relaxed its membership rules and a substantial increase in the number of borrowers is expected. Find the number of additional counters to be provided if the arrival rate is expected to be twice the present value and the average waiting time of the borrower must be limited to half the present value.
Answer :
Word Count : 304
The present system is an (M/M/2) queue. Borrowers arrive according to a Poisson process at the rate of 2 every 10 minutes, so the arrival rate is (\lambda = 0.2) per minute. The mean service time is 15 minutes, hence the service rate per counter is (\mu = 1/15 = 0.0667) per minute. With two counters, the traffic intensity is [ \rho = \frac{\lambda}{2\mu} = \frac{0.2}{2\times 0.0667} = 1.5. ] Since (\rho > 1), the present _______ _______ _________ _______ __________ ______ _______ _____ __________ __________ _________ ___.
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The present system is an (M/M/2) queue. Borrowers arrive according to a Poisson process at the rate of 2 every 10 minutes, so the arrival rate is (\lambda = 0.2) per minute. The mean service time is 15 minutes, hence the service rate per counter is (\mu = 1/15 = 0.0667) per minute. With two counters, the traffic intensity is [ \rho = \frac{\lambda}{2\mu} = \frac{0.2}{2\times 0.0667} = 1.5. ] Since (\rho > 1), the present _______ _______ _________ _______ __________ ______ _______ _____ __________ __________ _________ ___.
______ _________ ____ ________ ____.
______ ______ ______ _________ _____ __________.
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______ ________ __________ ____ __________.
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