a) Integrate
To evaluate the given integral:
∫^1_0 tan^1(2x/(i-x^2)) dx
We need to substitute u = 2x/(i-x^2) and then use the inverse trigonometric substitution.
Let u = 2x/(i-x^2)
du = (2(i-x^2) - 2x(-2x))/(i-x^2)^2 dx
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