Question

a) Integrate \int ^1_0tan^1\left ( \frac{2x}{i-x^2} \right )dx..

11 Mar 2024
Answer :
Word Count : 227

To evaluate the given integral:

∫^1_0 tan^1(2x/(i-x^2)) dx

We need to substitute u = 2x/(i-x^2) and then use the inverse trigonometric substitution.

Let u = 2x/(i-x^2)
du = (2(i-x^2) - 2x(-2x))/(i-x^2)^2 dx
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