A husband and wife appear in an interview for two vacancies in the same post. The probability of husband’s selection is 18 and that of wife’s selection is ¼. What is the probability that:
(i) Both of them will be selected
(ii) Only one of them will be selected
(iii) None of them will be selected.

To solve this problem, we can use basic principles of probability. Let's denote the events as follows:

- Event H: Husband is selected
- Event W: Wife is selected

Given probabilities:
- P(H) = 1/8 (for husband's selection)
- P(W) = 1/4 (for wife's selection)

Now, let's calculate the probabilities for the given scenarios:

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