Question
A germanium crystal with doping of 1018 arsenic atoms per cm3 is required. For initial Ge load of 20 kg, calculate the mass of arsenic to be added. Assume that the value of k0 remains constant throughout the growth process. Consider the density of molten germanium to be 5.7 g cm-3 and atomic weight of arsenic 74.934u.
Answer :
Word Count : 378
To solve this numerically, we can use the following steps: ### Step 1: Calculate the number of moles of germanium (Ge) in 20 kg. - The atomic weight of germanium (Ge) is approximately 72.63 g/mol. - Mass of germanium = 20 kg = 20,000 g. Number of moles of germanium (\(n_{\text{Ge}}\)) = \(\frac{\text{Mass of Ge}}{\text{Atomic weight of Ge}}\) \[ n_{\text{Ge}} = \frac{20000 \, \text{g}}{72.63 \, \text{g/mol}} = 275.6 \, \text{mol} \] ### Step 2: Calculate _____ ________ ________ ______ _____ _________ ______ __________ __________.
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To solve this numerically, we can use the following steps: ### Step 1: Calculate the number of moles of germanium (Ge) in 20 kg. - The atomic weight of germanium (Ge) is approximately 72.63 g/mol. - Mass of germanium = 20 kg = 20,000 g. Number of moles of germanium (\(n_{\text{Ge}}\)) = \(\frac{\text{Mass of Ge}}{\text{Atomic weight of Ge}}\) \[ n_{\text{Ge}} = \frac{20000 \, \text{g}}{72.63 \, \text{g/mol}} = 275.6 \, \text{mol} \] ### Step 2: Calculate _____ ________ ________ ______ _____ _________ ______ __________ __________.
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