Question
a) For the lowest wave number absorption line in its rotational spectrum occurs at 41.11
Calculate the wave numbers corresponding to its second, third and fourth absorption lines. Explain the term, rotational spacing using these values.
Answer :
Word Count : 379
### Given Data: For \( ^1H^{19}F \), the lowest wave number absorption line in its rotational spectrum occurs at: \[ \tilde{\nu}_1 = 41.11 \, \text{cm}^{-1} \] ### Step 1: Understanding Rotational Absorption Lines For a rigid rotor, the energy levels in rotational spectroscopy are given by: \[ E_J = B J (J+1) \] where \( B \) is the rotational constant and \( J \) is the rotational quantum number. The selection rule for rotational transitions is: \[ \Delta J = +1 \] Thus, the wavenumber of the rotational transitions is given by: \[ ________ _______ __________ __________ _______.
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### Given Data: For \( ^1H^{19}F \), the lowest wave number absorption line in its rotational spectrum occurs at: \[ \tilde{\nu}_1 = 41.11 \, \text{cm}^{-1} \] ### Step 1: Understanding Rotational Absorption Lines For a rigid rotor, the energy levels in rotational spectroscopy are given by: \[ E_J = B J (J+1) \] where \( B \) is the rotational constant and \( J \) is the rotational quantum number. The selection rule for rotational transitions is: \[ \Delta J = +1 \] Thus, the wavenumber of the rotational transitions is given by: \[ ________ _______ __________ __________ _______.
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