a) For a conductor, number of collisions per second is and

Question

a) For a conductor, number of collisions per second is $10^{12},$ and plasma frequency is $\omega _P=2\pi \times 10^{15}.$

Calculate the skin depth for the signal frequency of (i) 50 $Hz,$ and (ii) 50 MHz.

13 Mar 2024

Answer :

Word Count : 265

To calculate the skin depth for the given signal frequencies of 50 Hz and 50 MHz in a conductor with a collision frequency of $10^{12}$ collisions per second and a plasma frequency of $\omega_P = 2\pi \times 10^{15}$, we'll use the formula for skin depth ($\delta$):

\[
\delta = \sqrt{\frac{2}{{\omega \mu_0 \mu_r \sigma}}}
\]

Where:
- $\omega$ is the angular frequency ($2\pi f$)
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