Question

a) For a conductor, number of collisions per second is 10^{12}, and plasma frequency is \omega _P=2\pi \times 10^{15}. 

Calculate the skin depth for the signal frequency of (i) 50 Hz, and (ii) 50 MHz. 

13 Mar 2024
Answer :
Word Count : 265

To calculate the skin depth for the given signal frequencies of 50 Hz and 50 MHz in a conductor with a collision frequency of \(10^{12}\) collisions per second and a plasma frequency of \(\omega_P = 2\pi \times 10^{15}\), we'll use the formula for skin depth (\(\delta\)):

\[
\delta = \sqrt{\frac{2}{{\omega \mu_0 \mu_r \sigma}}}
\]

Where:
- \(\omega\) is the angular frequency (\(2\pi f\))
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