Question
a) Find the integrating factor of the differential equation
and hence solve it.
Answer :
Word Count : 581
To solve the given differential equation \((6xy - 3y^2 + y)dx + 2(x - y)dy = 0\), we will first find its integrating factor and then solve it. ### Step 1: Check for exactness The given differential equation is: \[ (6xy - 3y^2 + y)dx + 2(x - y)dy = 0 \] We can identify the components as: \[ M(x, y) = 6xy - 3y^2 + y \quad \text{and} \quad N(x, y) = 2(x - y) \] To check if the equation is exact, we need to compute the partial derivatives of \(M\) and \(N\) with respect to \(y\) and \(x\) respectively. - \(\frac{\partial M}{\partial y} = \frac{\partial}{\partial y}(6xy - 3y^2 + y) = 6x - ___ ___ ______ _____ _________ ________ ____ _______ _____ ______ ________ _________.
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To solve the given differential equation \((6xy - 3y^2 + y)dx + 2(x - y)dy = 0\), we will first find its integrating factor and then solve it. ### Step 1: Check for exactness The given differential equation is: \[ (6xy - 3y^2 + y)dx + 2(x - y)dy = 0 \] We can identify the components as: \[ M(x, y) = 6xy - 3y^2 + y \quad \text{and} \quad N(x, y) = 2(x - y) \] To check if the equation is exact, we need to compute the partial derivatives of \(M\) and \(N\) with respect to \(y\) and \(x\) respectively. - \(\frac{\partial M}{\partial y} = \frac{\partial}{\partial y}(6xy - 3y^2 + y) = 6x - ___ ___ ______ _____ _________ ________ ____ _______ _____ ______ ________ _________.
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