A 2.6 MeV neutron collides with hydrogen. Calculate the probability th

Question

A 2.6 MeV neutron collides with hydrogen. Calculate the probability that the energy of neutron is within the energy range 0.63 and 0.75 MeV after collision? If a neutron loses 0.75 MeV in LAB system, what is the scattering angle in the CM system?

19 Apr 2025

Answer :

Word Count : 360

In neutron-hydrogen collisions, the probability of the neutron's energy after the collision can be analyzed using the concept of neutron energy loss in elastic scattering. The total energy loss in the laboratory (LAB) frame is determined by the energy transfer due to the collision, which is dependent on the scattering angle in the center of mass (CM) frame.

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