Question
7) a) Le l be the ternary narrow-sense
code of designed distance
which has defining set
Use the primitive root 8th root of unity you chose in 4a) to avoid recomputing the the table of powers. If
Figure 1: Encoder for convolutional code.
is the generator polynomial of and
is the received word, find the transmitted codeword.
Answer :
Word Count : 1405
Let’s break this problem into steps. --- ## 1. Understand the problem This is an error-correction coding problem where: - We have a ternary narrow-sense BCH code (over \( GF(3) \)) with a certain designed distance. - Defining set \( T \) is given, probably in the original full problem statement but missing here. - They mention a primitive 8th root of unity chosen in problem 4a (not provided here), so we need to recall or reconstruct that. - We have a generator polynomial \( g(x) \) for a convolutional code ? — wait, reading carefully, it says: “is the generator polynomial of % and … is the received word, find the transmitted codeword.” The convolutional code diagram is just Figure 1, maybe not directly relevant — maybe the problem is actually about a cyclic block code not convolutional. The received word is given in polynomial form but cut off in the text you provided. --- My guess from standard problems: We have a primitive 8th root of unity \( \alpha \) in \( GF(3^m) \) for \( m \) such that \( 8 \mid 3^m - 1 \). For \( GF(3) \), smallest \( m \) such that \( 8 \mid 3^m - 1 \) is \( m=2 \)? Check: \( 3^2 - 1 = 8 \), yes. So \( GF(9) \) contains primitive 8th roots of unity. Let’s say \( \alpha \) is a primitive 8th root of unity in \( GF(9) \) with primitive polynomial \( x^2 + x + 2 \) or \( x^2 + 1 \) over \( GF(3) \) — but \( x^2 + 1 \) is irreducible over \( GF(3) \) since \( -1 \equiv 2 \), no, check: \( x^2 + 1 \) mod 3: \( 0^2+1=1\), \( 1^2+1=2\), \( 2^2+1=5\equiv 2\), never 0, so irreducible, so \( GF(9) \cong GF(3)[x]/(x^2+1) \). Let \( \beta \) be a root: \( \beta^2 + 1 = 0 \), so \( \beta^2 = 2 \). Now \( \beta^4 = 4 \equiv 1 \) mod 3? Wait \( 2^2 = 4 \equiv 1 \) mod 3, yes, ___ ___ ______ ______ _________ _____ __________ ________.
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Let’s break this problem into steps. --- ## 1. Understand the problem This is an error-correction coding problem where: - We have a ternary narrow-sense BCH code (over \( GF(3) \)) with a certain designed distance. - Defining set \( T \) is given, probably in the original full problem statement but missing here. - They mention a primitive 8th root of unity chosen in problem 4a (not provided here), so we need to recall or reconstruct that. - We have a generator polynomial \( g(x) \) for a convolutional code ? — wait, reading carefully, it says: “is the generator polynomial of % and … is the received word, find the transmitted codeword.” The convolutional code diagram is just Figure 1, maybe not directly relevant — maybe the problem is actually about a cyclic block code not convolutional. The received word is given in polynomial form but cut off in the text you provided. --- My guess from standard problems: We have a primitive 8th root of unity \( \alpha \) in \( GF(3^m) \) for \( m \) such that \( 8 \mid 3^m - 1 \). For \( GF(3) \), smallest \( m \) such that \( 8 \mid 3^m - 1 \) is \( m=2 \)? Check: \( 3^2 - 1 = 8 \), yes. So \( GF(9) \) contains primitive 8th roots of unity. Let’s say \( \alpha \) is a primitive 8th root of unity in \( GF(9) \) with primitive polynomial \( x^2 + x + 2 \) or \( x^2 + 1 \) over \( GF(3) \) — but \( x^2 + 1 \) is irreducible over \( GF(3) \) since \( -1 \equiv 2 \), no, check: \( x^2 + 1 \) mod 3: \( 0^2+1=1\), \( 1^2+1=2\), \( 2^2+1=5\equiv 2\), never 0, so irreducible, so \( GF(9) \cong GF(3)[x]/(x^2+1) \). Let \( \beta \) be a root: \( \beta^2 + 1 = 0 \), so \( \beta^2 = 2 \). Now \( \beta^4 = 4 \equiv 1 \) mod 3? Wait \( 2^2 = 4 \equiv 1 \) mod 3, yes, ___ ___ ______ ______ _________ _____ __________ ________.
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