Word Count : 296

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We are asked to express [ \frac{x-1}{x^3 - x^2 - 2x} ] as a sum of partial fractions. First, factor the denominator: [ x^3 - x^2 - 2x = x(x^2 - x - 2) = x(x-2)(x+1) ] So we have: [ \frac{x-1}{x(x-2)(x+1)} ] Let us express it as: [ _______ ____ _____ ________ __________ ______ ________ _____ __________ ____.
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