Word Count : 146

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यदि $f(x)=e^{ax}$ हो, तो पहले अग्रगामी अन्तर-चिह्न की परिभाषा से $$ \Delta f(x)=f(x+h)-f(x)=e^{a(x+h)}-e^{ax}=e^{ax}\big(e^{ah}-1\big). $$ इससे स्पष्ट है कि $n=1$ के लिए आवश्यकता सिद्ध हो गयी। अब गणितीय प्रेरणा (mathematical _________ _________ _________ __________ __________ ___ ____ ____ ____ _____ _____ __________.
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