Word Count : 192

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सदिशों \(\mathbf{A} = \sqrt{2} \hat{i} + 2 \hat{j} + 2 \hat{k}\) और \(\mathbf{B} = \hat{i} + \sqrt{2} \hat{j} + \sqrt{2} \hat{k}\) के बीच का कोण ज्ञात करने के लिए हम dot product का उपयोग करेंगे। ### डॉट प्रोडक्ट सूत्र: \[ \mathbf{A} \cdot \mathbf{B} = |\mathbf{A}| |\mathbf{B}| \cos \theta ______ _____ _______ ___ _____ __________ _________ ______ ____ __________ ______.
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