Word Count : 231

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मान लीजिए $\displaystyle \frac{dx}{y-z}=\frac{dy}{z-x}=\frac{dz}{x-y}=dt$ तो हम लिख सकते हैं $$ \dot x=\frac{dx}{dt}=y-z,\qquad \dot y=z-x,\qquad \dot z=x-y. $$ (1) प्रथम समाकलन — योग का स्थिरता : $$ \frac{d}{dt}(x+y+z)=\dot x+\dot y+\dot z=(y-z)+(z-x)+(x-y)=0 $$ अतः $$ x+y+z=C_1\quad(\text{स्थायी स्थिरांक}). $$ (2) द्वितीय _____ ___ __________ __________ _____.
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