Word Count : 174

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(i) (\displaystyle \lim_{x \to +\infty} \left( \frac{x^2}{8x^2 - 3} \right)^{1/3}) सबसे पहले अन्दर के अनुपात पर ध्यान दें: [ \frac{x^2}{8x^2 - 3} = \frac{x^2}{x^2(8 - 3/x^2)} = \frac{1}{8 - 3/x^2} ] जब (x \to +\infty), तो (3/x^2 \to 0)। अतः: [ \frac{x^2}{8x^2 - ___ _____ ______ ______ ________ _____ ________ ____ ________ ______ _________.
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