Word Count : 402

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दिया गया सदिश क्षेत्र \(\vec{A}\) है: \[ \vec{A} = (\rho z \hat{e}_{\rho} + \rho^2 \hat{e}_{\phi} + \rho z \sin\phi \hat{e}_{z}) \] अब हमें इसका डाइवर्जेन्स और कर्ल निकालने हैं। ### 1. डाइवर्जेन्स (\(\nabla \cdot \vec{A}\)): डाइवर्जेन्स का सूत्र इस प्रकार होता है: \[ \nabla \cdot \vec{A} = \frac{1}{\rho} \frac{\partial}{\partial \rho} (\rho A_{\rho}) + \frac{1}{\rho} \frac{\partial}{\partial \phi} A_{\phi} + \frac{\partial}{\partial z} A_{z} \] यहाँ \(\vec{A}\) के घटक हैं: - \(A_{\rho} = \rho z\) - \(A_{\phi} = \rho^2\) - \(A_{z} = \rho __________ ______ ______ _________ ___ ______ ________ ____ _________ ____.
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