Word Count : 331

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हमारे पास दी गई दीर्घवृत्त (ellipse) का समीकरण है: $$ \frac{x^2}{16} + \frac{y^2}{4} = 1 $$ यह दीर्घवृत्त x-अक्ष के समानांतर क्षैतिज अक्ष पर केंद्रित है क्योंकि $\frac{x^2}{a^2}$ का हरमान (denominator) बड़ा है। --- ### चरण 1: दीर्घवृत्त के मानक समीकरण से तुलना सामान्य रूप: $$ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1, \quad a^2 > b^2 $$ जहाँ: * केंद्र = $(0,0)$ * मुख्य अक्ष = x-अक्ष * सह-अक्ष = y-अक्ष यहाँ: * $a^2 = 16 \Rightarrow a = 4$ * $b^2 = __________ ________ __________ _________ ____ ________ _________.
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