b) Describe the Function Approximation in MLP. Also, explain Generalization of MLP.
See Answer →a) Define Kohonen networks with examples.
See Answer →Consider the set of pattern vectors P. Obtain the connectivity matrix (CM) for the patterns in P (four patterns).
b) Write the types of Neural Memory Models. Also, give one example of each.
See Answer →a) Define Error Correction Learning with examples.
See Answer →Consider a dataset of six points given in the following table, each of which has two features and
Assuming the values of the parameters c and m as 2 and the initial cluster centers
and
apply FCm algorithm to find the new cluster center after one iteration.
| 3 | 11 | |
| 3 | 10 |
| 8 | 12 | |
| 10 | 6 | |
| 13 | 6 | |
| 13 | 5 |
See Answer →
Let A and B are two fuzzy sets and and
then find out the following membership values:
i) ii)
iii)
iv) v)
vi)
b) Apply the “very” hedge on the fuzzy sets defined in Q. 1(b) to get the new modified fuzzy sets. Show the modified fuzzy sets through numeration.
See Answer →a) Construct the α − cut at α = 4.0 for the fuzzy sets defined in Q. 1(b)
See Answer →b) Consider a subset of natural numbers from 1 to 30, as the universe of discourse, U. Define the fuzzy sets “small” and “medium” by enumeration.
See Answer →a) Two sensors based upon their detection levels and gain settings are compared. The following of gain setting and sensor detection levels with a standard item being monitored provides typical membership values to represent the detection levels for each of the sensors.
| Gain Setting | Sensor detection levels | Sensor 2 detection levels |
| 0 | 0 | 0 |
| 20 | 0.5 | 0.35 |
| 40 | 0.65 | 0.5 |
| 60 | 0.85 | 0.75 |
| 80 | 1 | 0.90 |
| 100 | 1 | 1 |
The universe of discourse is Find the membership function for the two sensors. Also, verify De-morgon’s laws for these membership functions.
Use Miller-Rabin test to check whether 75521 is a strong pseuodprime to the base 2.
See Answer →Find the inverse of 13 (mod 51) using extended euclidean algorithm
See Answer →Another version of the columnar transposition cipher is the cipher using a key word. In this cipher, we encrypt as follows: Given a key word, we remove all the duplicate characters in the key word. For example, if the key word is ‘SECRET’, we remove the second ‘E’ and use ‘SECRT’ as the key word. To encrypt, we form a table as follows: In the first row, we write down the key word. In the following rows, we write the plaintext. Suppose we want to encrypt the text ‘ATTACKATDAWN’. We make a table as follows:
| S | E | C | R | T |
| A | T | T | A | C |
| K | A | T | D | A |
| W | N | X | X | X |
Then we read off the columns in alphabetical order. We first read the column under ‘C’, followed by the columns under ‘E’, ‘R’, ‘S’ and ‘T’. We get the cipher text TTX TAN ADX AKW CAX. To decrypt, we reverse the process. Note that, since we know the length of the keyword, we can find the length of the columns by dividing the length of the message by the length of the keyword. Given the ciphertext ‘HNDWUEOESSRORUTXLARFASUXTINOOGFNEGASTORX’ and the key word ‘LANCE’, find the plaintext.
See Answer →b) Draw the Tanner graph of the code L with parity check matrix
c) Find the convolutional code for the message 11011. The convolutional encoder is given in Fig. 1.
See Answer →Text:"KSTYZKESLNZUV", encrypted with Vigenère cipher with key "RESULT"
See Answer →Text: "CBBGYAEBBFZCFEPXYAEBB", encrypted with affine cipher with key (7,2)
See Answer →Let
We represent the field
by
LEt us write
the table of values is given below:
| i | Vector | i | Vector | ||
| 0 | 1 | (0,0,0,1) | 8 | (0,1,0,1) | |
| 1 | (0,0,1,0) | 9 | (1,0,1,0 | ||
| 2 | (0,0,1,0) | 10 | (0,1,1,1) | ||
| 3 | (1,0,0,0) | 11 | (1,1,1,0) | ||
| 4 | (1,0,0,0) | 12 | (1,1,1,1) | ||
| 5 | (0,1,1,0) | 13 | (1,1,0,1) | ||
| 6 | (1,1,0,0) | 14 | (1,0,0,1) | ||
| 7 | (1,0,1,1) |
i) Prepare logarithm and antilogarithm tables as given in page 23 of block 1.
ii) Compute using the logarithm and antilogarithm tables.
c) Find the generating idempotents of duadic codes of length n = 23 over (Hint: Mimic example 6.1.7.)