Levels of measurement
See Answer →Comparison between Spearman’s rho and Kendall’s tau
See Answer →Interactional effect
See Answer →Standard error
See Answer →Assumptions underlying regression
See Answer →Part correlation
See Answer →Scatter diagram
See Answer →Type I and type II errors
See Answer →Advantages and disadvantages of descriptive statistics
See Answer →Measures of central tendency
See Answer →Compute Chi-square for the following data:
| Managers | Work Motivation | |
| High | Low | |
| Junior Managers | 10 | 12 |
| Seniro Managers | 12 | 22 |
See Answer →
Compute Mann Whitney U test for the following data:
| Scores obtained on Emotional Intelligence Scale | ||||||||||
| Males | 32 | 34 | 54 | 31 | 32 | 67 | 39 | 38 | 40 | 23 |
| Females | 21 | 25 | 26 | 43 | 45 | 20 | 49 | 10 | 41 | 9 |
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Describe biserial and tetrachoric correlations with the help of suitable examples.
See Answer →Explain how the data can be organised using classification and tabulation
| Data A | 34 | 43 | 32 | 56 | 34 | 35 | 46 | 23 | 23 | 34 |
| Data B | 15 | 19 | 12 | 29 | 12 | 13 | 23 | 10 | 6 | 13 |
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Explain how the data can be organised using classification and tabulation
See Answer →The scores obtained by early, middle and late adolescents on adjustment scale are given below. Compute ANOVA for the same.
| Early adolescents | 2 | 3 | 2 | 3 | 4 | 2 | 4 | 5 | 2 | 2 |
| Middle adolescents | 3 | 2 | 4 | 2 | 4 | 3 | 2 | 4 | 3 | 4 |
| Late adolescents | 7 | 6 | 5 | 4 | 2 | 3 | 4 | 4 | 3 | 2 |
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Explain the concept of normal distribution. Explain divergence from normality.
See Answer →Describe the assumptions, advantages and disadvantages of non-parametric statistics.
See Answer →Myth
See Answer →Androgyny
See Answer →